In a meter Bridge experiment resistance x is connected in the right gap. When R 1 and R 2 are connected in the left gap separately the balance points are 40 cm and 50 cm respectively from the left end. Now if both R 1 & R 2 are connected in series in the left gap with x in the right gap then the new balance point from the left end will be
Text Solution
Verified by ExpertsThe correct answer is:
B
= 
= 
.... (1),
= 
= 1 ..... (2)
= 
.... (3)
Add eq (1) & (2)
= 
+ 1 = 
... (4)
Placing eq (4) in (3)
5/ 3 = 
⇒ 500–5 λ = 3 λ
⇒ 8 λ =500 ∴ λ = 62.5 cms
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